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# Three coins are tossed once.Find the probability of getting no head

$\begin{array}{1 1}(A)\;\large\frac{1}{8}\\(B)\;\large\frac{2}{7}\\(C)\;\large\frac{1}{7}\\(D)\;\large\frac{1}{6}\end{array}$

Step 1:
If three coins are tossed,then the possible outcomes =$2^3=8$
$\therefore$ The sample space $S=\{HHH,HHT,HTH,HTT,THH,THT,TTH,TTT\}$
Step 2:
Let E be the event of getting no head
$\therefore n(E)=1$
Probability of getting no head =$\large\frac{n(E)}{n(S)}$
$\Rightarrow \large\frac{1}{8}$
Hence (A) is the correct answer.