$\begin{array}{1 1}(A)\;\large\frac{9}{11}\\(B)\;\large\frac{8}{11}\\(C)\;\large\frac{5}{11}\\(D)\;\large\frac{6}{11}\end{array} $

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- Sum of the event and its complementary event is always 1
- $\therefore P(A)+P(A')=1$

Let A be the event

Given $P(A)=\large\frac{2}{11}$

$\therefore$ P(not A)=P(A')=1-P(A)

$\Rightarrow 1-\large\frac{2}{11}$

$\Rightarrow\large\frac{9}{11}$

$\therefore P(A')=\large\frac{9}{11}$

Hence (A) is the correct answer.

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