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Home  >>  CBSE XI  >>  Math  >>  Probability
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Given $P(A)=\large\frac{3}{5}$ and $P(B)=\large\frac{1}{5}$.Find P(A or B),if $A$ and $B$ are mutually exclusive events .

$\begin{array}{1 1}(A)\;\large\frac{4}{5}\\(B)\;\large\frac{2}{5}\\(C)\;\large\frac{6}{5}\\(D)\;\text{None of these}\end{array} $

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1 Answer

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Toolbox:
  • The formula used to solve this problem is $P(A\cup B)=P(A)+P(B)-P(A \cap B)$
Given A and B are mutually exclusive events.
$\therefore$ Mutually exclusive means $P(A \cap B)=\phi$
$\therefore$ P(A or B)=$P(A \cup B)=P(A)+P(B)-P(A \cap B)$
$\Rightarrow \large\frac{3}{5}+\frac{1}{5}$$-0$
$\Rightarrow \large\frac{3+1}{5}$
$\Rightarrow \large\frac{4}{5}$
$\therefore$ P( A or B)=$\large\frac{4}{5}$
Hence (A) is the correct answer.
answered Jul 1, 2014 by sreemathi.v
 

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