Browse Questions

# Find the mean deviation about the mean of the distribution

$\begin{array}{1 1}(A)\;10.10,1.99\\(B)\;8.4,5.6\\(C)\;3,8\\(D)\;21.65,1.25\end{array}$

Toolbox:
• The formula used to solve this problem are
• Mean $\bar{x}=\large\frac{\sum f_ix_i}{\sum f_i}$
• Mean deviation about mean $=\large\frac{\sum f_i | x_i - \bar{x}|}{\sum f_i }$
Step 2:
Mean $\bar {x} =\large\frac{\sum f_i x_i}{\sum f_i}$
$\qquad= \large\frac{433}{20} $$=21.65 Step 2: Mean deviation about mean =\large\frac{\sum f_i | x_i - \bar{x}|}{\sum f_i } \qquad= \large\frac{25}{20}$$=1.25$
Hence D is the correct answer.