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Home  >>  CBSE XI  >>  Math  >>  Probability
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A and B are two events such that P(A)=0.54,P(B)=0.69 and $P(A\cap B)=0.35$.Find $P(A\cap B')$

$\begin{array}{1 1}(A)\;0.19\\(B)\;0.29\\(C)\;0.39\\(D)\;0.49\end{array} $

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1 Answer

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  • $P(A\cap B')=P(A)-P(A \cap B)$
$P(A)=0.54$
$P(B)=0.69$
$P(A \cap B)=0.35$
$P(A\cap B')=P(A)-P(A \cap B)$
$\Rightarrow 0.54-0.35$
$\Rightarrow 0.19$
Hence (A) is the correct answer.
answered Jul 2, 2014 by sreemathi.v
 

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