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Home  >>  CBSE XI  >>  Math  >>  Straight Lines
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Choose the correct answer from the given four options. If the coordinates of the middle point of the portion of a line intercepted between the coordinate axes is (3, 2), then the equation of the line will be

$\begin {array} {1 1} (A)\;2x + 3y = 12 & \quad (B)\;3x + 2y = 12 \\ (C)\;4x – 3y = 6 & \quad (D)\;5x – 2y = 10 \end {array}$

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1 Answer

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Toolbox:
  • The coordinates of the midpoint of the line joining the points $(x_1, y_1)$ and $(x_2, y_2)$ is $ \bigg( \large\frac{x_1+x_2}{2}$$, \large\frac{y_1+y_2}{2} \bigg)$
  • Equation of a line in its intercept form is $ \large\frac{x}{a}$$+\large\frac{y}{b}$$=1$ , where $a$ and $b$ are the intercepts in the coordinate axes.
Step 1 :
It is given that the mid point of a line intercepted between the coordinate axes is (3, 2)
Let the equation of the line be
$ \large\frac{x}{a}$$+ \large\frac{y}{b}$$=1$
Let the points A be $(a,o)$ and B be (0, b) and $p(3, 2)$
Since $p$ is the mid point of AB
$ \large\frac{a+0}{2}$$=3 \Rightarrow a = 6$ and
$ \large\frac{b+0}{2}=2 \Rightarrow b = 4$
$ \therefore $ The equation of the line is
$ \large\frac{x}{6}$$+ \large\frac{y}{4}$$=1$
$ \Rightarrow 2x+3y=12$
Hence 'A' is the correct option.
answered Jul 2, 2014 by thanvigandhi_1
 

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