Step 1 :
It is given that the mid point of a line intercepted between the coordinate axes is (3, 2)
Let the equation of the line be
$ \large\frac{x}{a}$$+ \large\frac{y}{b}$$=1$
Let the points A be $(a,o)$ and B be (0, b) and $p(3, 2)$
Since $p$ is the mid point of AB
$ \large\frac{a+0}{2}$$=3 \Rightarrow a = 6$ and
$ \large\frac{b+0}{2}=2 \Rightarrow b = 4$
$ \therefore $ The equation of the line is
$ \large\frac{x}{6}$$+ \large\frac{y}{4}$$=1$
$ \Rightarrow 2x+3y=12$
Hence 'A' is the correct option.