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Home  >>  CBSE XI  >>  Math  >>  Straight Lines
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Choose the correct answer from the given four options. A line cutting off intercept – 3 from the y-axis and the tangent at angle to the x - axis is $ \large\frac{3}{5}$, its equation is

$\begin {array} {1 1} (A)\;5y-3x+15=0 & \quad (B)\;3y-5x + 15 = 0 \\ (C)\;5y – 3x – 15=0 & \quad (D)\;\text{None of these} \end {array}$

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  • Equation of a line whose slope 'm' is given and intercept from the y - axis given is $y=mx+c$
Step 1 :
Intercept cutting off from y - axis is -3.
Slope of the tangent is $ \large\frac{3}{5}$
$ y = \large\frac{3}{5}$$x-3$
$ \Rightarrow 5y=3x-15$
(i.e) $5y-3x+15=0$ is the required equation of the line.
Hence A is the correct option.
answered Jul 2, 2014 by thanvigandhi_1

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