$\begin {array} {1 1} (A)\;5y-3x+15=0 & \quad (B)\;3y-5x + 15 = 0 \\ (C)\;5y – 3x – 15=0 & \quad (D)\;\text{None of these} \end {array}$

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- Equation of a line whose slope 'm' is given and intercept from the y - axis given is $y=mx+c$

Step 1 :

Intercept cutting off from y - axis is -3.

Slope of the tangent is $ \large\frac{3}{5}$

$ y = \large\frac{3}{5}$$x-3$

$ \Rightarrow 5y=3x-15$

(i.e) $5y-3x+15=0$ is the required equation of the line.

Hence A is the correct option.

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