Step 1 :
The angle between the lines is given as $60^{\circ}$ and $ 0^{\circ}$.
Hence the slope 'm' is $ \tan 60^{\circ} = \sqrt 3 $ and $ \tan 0 = 0$
The line passing through the point (3,-2)
Hence the equation of the line is when $m =\sqrt 3 $
$ y-(-2)=\sqrt 3 (x-3)$
$ y+2=\sqrt 3x-3\sqrt 3$
$ \Rightarrow \sqrt 3x-y-2-3\sqrt 3 $
The equation of the line when $m = 0 $ is $y-(-2)=0$
$ \Rightarrow y + 2 = 0$
Hence the equation of the required lines are
$ y+2=0$ and $\sqrt 3 x-y-2-3\sqrt 3$
Hence 'A' is the correct option.