$\begin{array}{1 1}(A)\;0.73\\(B)\;0.93\\(C)\;0.63\\(D)\;0.43\end{array} $

- $P(A \cup B)=P(A)+P(B)-P(A\cap B)$

Step 1:

Probability that a family owns a colour television P(A)=0.87

Probability that a family owns a black & white P(B)=0.36

Probability that a family owns both P($A \cap B$)=0.30

Probability that a family owns either anyone or both $P(A \cup B)$=?

Step 2:

$P(A \cup B)=P(A)+P(B)-P(A \cap B)$

$\Rightarrow 0.87+0.36-0.30$

$\Rightarrow 0.93$

Hence the answer is 0.93

Hence (B) is the correct answer.

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