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Home  >>  CBSE XI  >>  Math  >>  Probability
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If A and B are mutually exclusive events,$P(A)=0.35$ and $P(B)=0.45$ find P(A')

$\begin{array}{1 1}(A)\;0.65\\(B)\;0.35\\(C)\;0.45\\(D)\;\text{None of these}\end{array} $

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1 Answer

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  • P(A')=1-P(A)
A and B are mutually exclusive events
$\therefore P(A \cap B)=\phi$
$P(A)=0.35$
P(A')=1-P(A)
$\quad\;\;=1-0.35$
$\quad\;\;=0.65$
Hence (A) is the correct answer.
answered Jul 7, 2014 by sreemathi.v
 

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