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Home  >>  CBSE XI  >>  Math  >>  Probability
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If A and B are mutually exclusive events,$P(A)=0.35$ and $P(B)=0.45$ find $P(A \cap B)$

$\begin{array}{1 1}(A)\;0\\(B)\;0.65\\(C)\;0.35\\(D)\;0.75\end{array} $

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A and B are mutually exclusive events
$\therefore P(A \cap B)=\phi$
$P(A \cap B)=0$
A and B are mutually exclusive events.
Hence (A) is the correct answer.
answered Jul 7, 2014 by sreemathi.v
 
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