# If A and B are mutually exclusive events,$P(A)=0.35$ and $P(B)=0.45$ find $P(A \cap B')$

$\begin{array}{1 1}(A)\;0.35\\(B)\;0.25\\(C)\;0.65\\(D)\;0.75\end{array}$

Toolbox:
• $P(A \cap B')=P(A)$
$P(A)=0.35$
$P(A \cap B')=P(A)$
$\Rightarrow 0.35$
Hence (A) is the correct answer.