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Home  >>  CBSE XI  >>  Math  >>  Probability
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If A and B are mutually exclusive events,$P(A)=0.35$ and $P(B)=0.45$ find $P(A \cap B')$

$\begin{array}{1 1}(A)\;0.35\\(B)\;0.25\\(C)\;0.65\\(D)\;0.75\end{array} $

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1 Answer

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  • $P(A \cap B')=P(A)$
$P(A)=0.35$
$P(A \cap B')=P(A)$
$\Rightarrow 0.35$
Hence (A) is the correct answer.
answered Jul 7, 2014 by sreemathi.v
 
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