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If A and B are mutually exclusive events,$P(A)=0.35$ and $P(B)=0.45$ find $P(A' \cap B')$

$\begin{array}{1 1}(A)\;0.20\\(B)\;0.30\\(C)\;0.40\\(D)\;0.50\end{array} $

1 Answer

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  • $P(A' \cap B')=P(A \cup B)'=1-P(A \cup B)$
$P(A' \cap B')=P(A \cup B)'$
$\Rightarrow 1-P(A \cup B)$
$\Rightarrow 1-0.80$
$\Rightarrow 0.20$
Hence (A) is the correct answer.
answered Jul 7, 2014 by sreemathi.v
 
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