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Home  >>  CBSE XI  >>  Math  >>  Probability
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The accompanying venn diagram shows three events A,B and C,and also the probabilities of the various intersections (for instance $P(A \cap B)=0.07$).Determine Probability of exactly one of the three occurs

$\begin{array}{1 1}(A)\;0.51\\(B)\;0.61\\(C)\;0.41\\(D)\;0.81\end{array} $

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1 Answer

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P(exactly one of the three occurs)=P(A only)+P(B only)+P(C only)
According to the venn diagram
$\Rightarrow 0.13+0.10+0.28$
$\Rightarrow 0.51$
Hence (A) is the correct answer.
answered Jul 8, 2014 by sreemathi.v
 

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