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# If the letters of the word ASSASSINATION are arranged at random.Find the probability that two I's and two N's come together.

$\begin{array}{1 1}(A)\;\large\frac{3}{143}\\(B)\;\large\frac{2}{143}\\(C)\;\large\frac{4}{143}\\(D)\;\large\frac{9}{143}\end{array}$

Step 1:
Given the word ASSASSINATION
Two I's and two N's come together
Considering two I's and two N's as one letter
$\therefore$ Total number of letters =10 and they can be arranged in 4! ways.
Step 2:
$\therefore P=\large\frac{10!}{13!}$$\times 4!$
$\Rightarrow \large\frac{2}{143}$
Hence (B) is the correct answer.