$\begin{array}{1 1}(A)\;\large\frac{25}{26}\\(B)\;\large\frac{22}{35}\\(C)\;\large\frac{15}{26}\\(D)\;\large\frac{5}{26}\end{array} $

Given the word : ASSASSINATION

All A's are not coming together

$\Rightarrow $1-All A's coming together

$\therefore$ Probability of all A's coming together=$\large\frac{11!}{13!}$$\times 3!$

$\Rightarrow \large\frac{1}{26}$

Step 2:

$\therefore$ Probability of A's are not coming together $=1-\large\frac{1}{26}$

$\Rightarrow \large\frac{25}{26}$

Hence (A) is the correct answer.

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