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Home  >>  CBSE XI  >>  Math  >>  Straight Lines
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Fill in the bank for the following : the line which cuts off equal intercept from the axes and pass through the point (1, -2) is _________.

$\begin {array} {1 1} (A)\;x+y-1=0 & \quad (B)\;x-y+1=0 \\ (C)\;x-y-1=0 & \quad (D)\;x+y+1=0 \end {array}$

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  • Equation of a line in its intercept form is $\large\frac{x}{a}$$ + \large\frac{y}{b}$$=1$ where $a$ and $b$ are the intercepts on the coordinate axes.
Step 1 :
Given $ a = b$
Hence the equation of the line is $ \large\frac{x}{a} $$+\large\frac{y}{a}$$=1$
$ \Rightarrow x+y=a$
It passes through the point (1, -2)
$ \therefore 1-2=a$
$ \Rightarrow a = -1 $
Hence equation of the line is $ \large\frac{x}{-1}$$+\large\frac{y}{-1}$$=1$
$ \Rightarrow x+y=-1 $ or $ x+y+1=0$
Hence the equation of the required line is $ x+y+1=0$
answered Jul 8, 2014 by thanvigandhi_1

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