$\begin{array}{1 1}(A)\;\large\frac{29}{52}\\(B)\;\large\frac{1}{2}\\(C)\;\large\frac{26}{51}\\(D)\;\large\frac{27}{51}\end{array} $

Generally there are two colors in a deck of cards.Red or black.

$\therefore$ Probability of dropping a red card first=$\large\frac{26}{52}$

Probability of dropping a red card in $2^{nd}$ chance=$\large\frac{26}{51}$

$\therefore$ Dropping either colour in 2! ways.

$\therefore$ Required probability =$\large\frac{26}{52}\times \frac{26}{51}$$\times 2!$

$\Rightarrow \large\frac{26}{51}$

Hence (C) is the correct answer.

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