logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  CBSE XI  >>  Math  >>  Straight Lines
0 votes

State whether the following statement is true or false and justify : The vertex of an equilateral triangle is (2, 3) and the equation of the opposite side is $x + y = 2$. Then the other two sides are $y - 3 = (2 \pm \sqrt3 ) (x - 2)$.

Can you answer this question?
 
 

1 Answer

0 votes
Toolbox:
  • Slope of a line $m$ which make an angle $ ' \theta '$ in the positive direction of x axis is $m = \tan \theta $.
  • Equation of a line with slope $m$ and passing through $(x_1, y_1)$ is $ y-y_1=m(x-x_1)$
Step 1 :
Let $A(2,3)$ be one vertex and $x+y=2$ be the opposite side of the given equilateral triangle.
Hence the other two sides pass through the point A(2,3) and make an angle $60^{\circ}$
Slope of the line $x+y=2$ is 1.
$m = -1$
$ \therefore $ Equation of the other two sides are
$ y-3 = \bigg( \large\frac{-1- \tan 60^{\circ}}{1-\tan 60^{\circ}} \bigg) $$(x-2)$
and $y-3 = \bigg( \large\frac{-1-\tan 60^{\circ}}{1+ \tan 60^{\circ}} \bigg) $$(x-2)$
But $\tan 60^{\circ} = \sqrt 3 $
$ \therefore y-3 = \large\frac{-1-\sqrt 3}{1-\sqrt 3 }$$(x-2)$
(i.e) $y-3=\large\frac{-(1+ \sqrt 3 )}{1-\sqrt 3}$$(x-2)$
(i.e) $ (y-3) = (2+\sqrt 3)(x-2)$
is the equation of one side.
$y-3 = \large\frac{\sqrt 3 - 1 }{\sqrt 3 + 1 }$$(x-2)$
$ \Rightarrow (y-3)(2+ \sqrt 3 )=(x-2)$ is the equation of the other side.
(i.e) $(y-3)=(2-\sqrt 3 )(x-2)$
Hence the statement is true.
answered Jul 9, 2014 by thanvigandhi_1
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...