Step 1:
Given four digit numbers are to be formed.
$\therefore$ The numbers can't be formed starting with zero.
$\therefore$ Total numbers formed
Starting with 2=3!=6
Starting with 3=3!=6
Starting with 5=3!=6
$\therefore$ total =6+6+6=18
Step 2:
The numbers being divisible with 5,have to end with 0 or 5
$\therefore$ Total such numbers =4+4+2=10
$\therefore$ Required probability =$\large\frac{10}{18}=\frac{5}{9}$
Hence (D) is the correct option.