Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  CBSE XI  >>  Math  >>  Probability
0 votes

6 boys and 6 girls sit in a row at random.The probability that all the girls sit together is

$\begin{array}{1 1}(A)\;\large\frac{1}{432}\\(B)\;\large\frac{12}{432}\\(C)\;\large\frac{1}{132}\\(D)\;\text{None of these}\end{array} $

Can you answer this question?

1 Answer

0 votes
Step 1:
Given 6 boys and 6 girls
$\therefore$ Number of ways in which 6 boys and 6 girls together sitting in a row =7!
6 girls sitting arrangement =6!
Step 2:
$\therefore$ Required probability =$\large\frac{7!\times 6!}{12!}$
$\Rightarrow \large\frac{1}{132}$
Hence (C) is the correct answer.
answered Jul 9, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App