$\begin{array}{1 1}(A)\;81 \\(B)\;57 \\(C)\;36 \\(D)\;25 \end{array} $

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Give the $SD = 5^{\circ}C$

Variance $=(S.D)^2$

$\qquad= (5^{\circ}C)^2$$=25^{\circ}C$

To convert $^{\circ}C$ to $^{\circ}F$

=> $ \large\frac{^{\circ}C \times 9}{5} $$+32$

=> $\large\frac{25^{\circ} C \times 9}{5} $$+32$

=> $45 +32= 77^{\circ}F$

The nearest answer is 81

Hence A is the correct answer.

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