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Home  >>  CBSE XI  >>  Math  >>  Statistics
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The standard deviation of some temperature data in $^{\circ} C$ is 5. If the data were converted into $^{\circ} F$ the variance would be

$\begin{array}{1 1}(A)\;81 \\(B)\;57 \\(C)\;36 \\(D)\;25 \end{array} $

Can you answer this question?
 
 

1 Answer

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Give the $SD = 5^{\circ}C$
Variance $=(S.D)^2$
$\qquad= (5^{\circ}C)^2$$=25^{\circ}C$
To convert $^{\circ}C$ to $^{\circ}F$
=> $ \large\frac{^{\circ}C \times 9}{5} $$+32$
=> $\large\frac{25^{\circ} C \times 9}{5} $$+32$
=> $45 +32= 77^{\circ}F$
The nearest answer is 81
Hence A is the correct answer.
answered Jul 9, 2014 by meena.p
 

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