Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  CBSE XI  >>  Math  >>  Statistics
0 votes

The standard deviation of some temperature data in $^{\circ} C$ is 5. If the data were converted into $^{\circ} F$ the variance would be

$\begin{array}{1 1}(A)\;81 \\(B)\;57 \\(C)\;36 \\(D)\;25 \end{array} $

Can you answer this question?

1 Answer

0 votes
Give the $SD = 5^{\circ}C$
Variance $=(S.D)^2$
$\qquad= (5^{\circ}C)^2$$=25^{\circ}C$
To convert $^{\circ}C$ to $^{\circ}F$
=> $ \large\frac{^{\circ}C \times 9}{5} $$+32$
=> $\large\frac{25^{\circ} C \times 9}{5} $$+32$
=> $45 +32= 77^{\circ}F$
The nearest answer is 81
Hence A is the correct answer.
answered Jul 9, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App