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# True-or-False : The probability that a student will pass his examination is 0.73,the probability of the student getting a compartment is 0.13,and the probability that the student will either pass or get compartment is 0.96.

$\begin{array}{1 1}(A)\;\text{True}\\(B)\;\text{False}\end{array}$

Toolbox:
• $P(A\cup B)=P(A)+P(B)-P(A \cap B)$
Given :
$P(A \cup B)=0.96$
$P(A)=0.73$
$P(B)=0.13$
$\therefore 0.96=0.73+0.13-P(A \cap B)$
$\Rightarrow P(A \cap B)=0.73+0.13-0.96$
$\Rightarrow 0.86-0.96$
$\Rightarrow -0.10$
The probability cannot be negative.
$\therefore$ The statement is False.