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Home  >>  CBSE XI  >>  Math  >>  Probability
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If A and B are two events associated with a random experiment such that $P(A)=0.3,P(B)=0.2$ and $P(A \cap B)=0.1$ then the value of $P(A \cap \bar{B})$ is _________

$\begin{array}{1 1}(A)\;0.2\\(B)\;0.3\\(C)\;0.4\\(D)\;\text{None of these}\end{array} $

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1 Answer

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  • $P(A \cap \bar{B})=P(A)-P(A\cap B)$
$P(A \cap \bar{B})$=P(A only)
$P(A \cap \bar{B})=P(A)-P(A\cap B)$
$\Rightarrow 0.3-0.1$
$\Rightarrow 0.2$
Hence (A) is the correct answer.
answered Jul 9, 2014 by sreemathi.v
 

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