$\begin{array}{1 1}(A)\;(a)-iv,(b)-iii,(c)-ii,(d)-i\\(B)\;(a)-iii,(b)-iv,(c)-i,(d)-ii\\(C)\;(a)-i,(b)-ii,(c)-iii,(d)-iv\\(D)\;\text{None of these}\end{array} $

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If $E_1$ and $E_2$ are the two mutually exclusive events-$E_1 \cap E_2=\phi$

If $E_1$ and $E_2$ are the mutually exclusive and exhaustive events-$E_1 \cap E_2=\phi,E_1 \cup E_2=S$

If $E_1$ and $E_2$ have common outcomes,then-$E_1 - E_2)\cup (E_1\cap E_2)=E_1$

If $E_1$ and $E_2$ are two events such that,$E_1\subset E_2$ -$E_1 \cap E_2=E_1$

Hence (A) is the correct answer.

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