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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Units and Measurement

The dimensional formula of magnetic flux is:

1 Answer

$F = qvB \sin \theta$
$\begin{align*}B = \frac{F}{qv} \sin \theta \end{align*}$
$\begin{align*} [B] &= \frac{[MLT^{-2}]}{[LT^{-1}][A^T] } \\ & = ML^OT^{-2}A^{-1}\end{align*}$
Hence Magnetic flux = BA
$\; \; \; \;= [MT^{-2}A^{-1}] [L^2]$
$\;\;\;\; = ML^2T^{-2}A^{-1}$
answered Jul 10, 2014 by balaji.thirumalai
edited Nov 27, 2017 by priyanka.c
 
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