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# What is the perimeter and area of a rectangle whose length is $6.01$ m and width is $1.2 m$

$\begin{array}{1 1}(A)\;14.42m,7.212m^2 \\(B)\;14m,7.2m^2 \\(C)\;14.4m,7.2m^2 \\(D)\;14.4m,7.21\;m^2 \end{array}$

Can you answer this question?

perimeter $= 2(6.01 m) +2(1.2 m)$
$\qquad= 14.42 \;m$
$\qquad= 14.4\; m$ (Retaining one doubtful figure)
area $= 6.01 m \times 1.2 m$
$\qquad= 7.212 m^2$
$\qquad= 7.2\;m^2$
Hence C is the correct answer.
answered Jul 10, 2014 by