$\begin{array}{1 1}(A)\;2.9 \times 10^6 \\(B)\;2.3 \times 10^4 \\(C)\;4.7 \times 10^4 \\(D)\;7.45 \times 10^2 \end{array} $

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Since the calculation involves several steps let us retain one extra digit in the intermediate steps. then $\large\frac{5.3 \times 10^4 }{3.3 \times 10^{-2}} +$$ \sqrt { 1.6 \times 10^{12}}$

$\qquad= 1.61 \times 10^6 + 1.26 \times 10^6$

$\qquad= 2.87 \times 10^6$

$\qquad= 2.9 \times 10^6$

Hence A is the correct answer.

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