$\begin{array}{1 1}(A)\;200\;cm \\(B)\;23 \;cm \\(C)\;98 \;cm \\(D)\;25\;cm \end{array} $

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$S_2P- S_1P= 100.1664\;cm -100.1243\;cm$

$\qquad= 0.0421\;cm$

The difference of two length have 3 significant figure. Now

$S_2P +S_1P =100.1664\;cm+100.1243\;cm$

$\qquad= 200.2907\;cm$

Since the number of significant figures in difference is 3, the number of significant figures in sum should also be 3 Thus,

$S_2P+S_1P=200\;cm$

Hence A is the correct answer.

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