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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Units and Measurement
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The distance of a point p from a point source of light $S_1$ is $100. 1243\;cm$ and from another point source $S_2$ is $100.1664\;cm$ Find $(S_2P-S_1P)$ and $(S_2P +S_1P)$ correct upto the same number of significant figures.

$\begin{array}{1 1}(A)\;200\;cm \\(B)\;23 \;cm \\(C)\;98 \;cm \\(D)\;25\;cm \end{array} $

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$S_2P- S_1P= 100.1664\;cm -100.1243\;cm$
$\qquad= 0.0421\;cm$
The difference of two length have 3 significant figure. Now
$S_2P +S_1P =100.1664\;cm+100.1243\;cm$
$\qquad= 200.2907\;cm$
Since the number of significant figures in difference is 3, the number of significant figures in sum should also be 3 Thus,
Hence A is the correct answer.
answered Jul 11, 2014 by meena.p

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