info@clay6.com
logo

Ask Questions, Get Answers

X
 
Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Motion in a Plane
Answer
Comment
Share
Q)

Two bodies are projected from the same point with the same speed but in different directions so as to have the same range. The ratio of their times of flight are .

$\begin{array}{1 1}(A)\;1:1\\(B)\;1:\cos \theta \\(C)\;1: \sin \theta\\(D)\;1: \cot \theta \end{array} $

1 Answer

Comment
A)
Need homework help? Click here.
For the same range for the same speed projected if $ \theta_1= \theta$ then
$\theta_2 =(90^{\circ}- \theta)$
$t_1=\large\frac{ 2 v_0 \sin \theta}{g}$ and
$t_2 = \large\frac{2 v_0 \cos \theta}{g}$
$\large\frac{t_2}{t_1} =\frac{ \cos \theta}{\sin \theta}$
$\qquad= \cot \theta$
Hence D is the correct answer.
Home Ask Homework Questions
...