Given that the pressure $p$ at a depth $h$ below the surface of a fluid of density $\rho$ is given by $p = \rho gh$, where $g$ is the acceleration due to gravity, which of the following represent the dimensions of pressure?

Answer 1

$[p] = [\large\frac{\text{force}}{\text{area}}]$$=\large\frac{MLT^{-2}}{L^2} $$=ML^{-1}T^{-2}$

OR

$[\rho] = ML^{-3}$

$[g] = LT^{-2}$ (acceleration)

$[h] = L$

$\Rightarrow [p] = [\rho gh] = ML^{-3}LT^{-2} = ML^{-1}T^{-2}$