Ask Questions, Get Answers
Menu
X
JEEMAIN Crash Practice
15 Test Series
NEET Crash Practice
5 Test Series
CBSE XII
Math
JEEMAIN
Math
Physics
Chemistry
Practice Test Series
CBSE XI
Math
NEET
Physics
Chemistry
Biology - XII
Biology - XI
Olympiad class V
Math - 5 Test Series
Olympiad class VI
Math - 5 Test Series
studyplans
JEEMAIN Crash Practice
15 Test Series
NEET Crash Practice
5 Test Series
CBSE XII
Math
JEEMAIN
Math
Physics
Chemistry
Practice Test Series
CBSE XI
Math
NEET
Physics
Chemistry
Biology - XII
Biology - XI
Olympiad class V
Math - 5 Test Series
Olympiad class VI
Math - 5 Test Series
mobile
exams
ask
sample papers
tutors
pricing
sign-in
Download our FREE mobile app with 1000+ tests for CBSE, JEE MAIN, NEET
X
Search
Topics
Want to ask us a question?
Click here
Browse Questions
Student Questions
Ad
Home
>>
JEEMAIN and AIPMT
>>
Physics
>>
Class11
>>
Units and Measurement
0
votes
The velocity v of a particle at time t is given by $v=a+ bt+\large\frac{c}{t+d}$ where a, b, c and d are constants. The dimensions of a, b c and d are respectively
jeemain
physics
class11
units-and-measurement
ch2
dimensional-formulae-and-analysis
medium
Share
asked
Jul 11, 2014
by
balaji.thirumalai
Please
log in
or
register
to add a comment.
Can you answer this question?
Do not ask me again to answer questions
Please
log in
or
register
to answer this question.
1 Answer
0
votes
From Dimensional Analysis' Principle of Homogeneity, $[a] = [v] $
$[a] = [LT^{-1}]$ and $[bt] = [v] \rightarrow [b] = \large\frac{[v]}{[t]}$$=\large\frac{[LT^{-1}]}{[T]}$
$\Rightarrow [b] = [LT^{-2}]$
Also, $[d] = [t] = T$
$\Rightarrow \large\frac{[c]}{[d+t]} $$= [v] \rightarrow [c] = [v][d+t]$
$\Rightarrow [c] = [LT^{-1}]{[T]} = [L]$
answered
Jul 11, 2014
by
balaji.thirumalai
Please
log in
or
register
to add a comment.
Related questions
0
votes
1
answer
The position $x$ of a particle at time $t$ is given by $x=\large\frac{v_0}{a} $$(1-e^{-at})$ where $v_0$ is constant and $a >0$ find the dimensions of $v_0$ and $a$
asked
Jun 17, 2013
by
meena.p
jeemain
physics
class11
ch2
units-and-measurement
q10
medium
dimensional-formulae-and-analysis
0
votes
1
answer
The equation of state of some gases can be expressed as $ \bigg(p+\large\frac{a}{v^2}\bigg)$$(v-b)=RT$ Here $p$ is pressure, $v$ is volume , $a,b,R$ are constants. The dimensions of $ 'a'$ are
asked
Jun 13, 2013
by
meena.p
jeemain
physics
class11
ch2
units-and-measurement
q1
easy
dimensional-formulae-and-analysis
0
votes
1
answer
Suppose we are told that the acceleration $A$ of a particle moving with uniform speed $v$ in a circle of radius $r$ is proportional to some power of r, say $r^n$, and some power of v, say $v^m$. Which of the following is the simplest form of an equation for the acceleration?
asked
Mar 23, 2014
by
balaji.thirumalai
jeemain
physics
class11
ch2
units-and-measurement
medium
dimensional-formulae-and-analysis
0
votes
1
answer
Suppose we are told that the acceleration $A$ of a particle moving with uniform speed $v$ in a circle of radius $r$ is proportional to some power of r, say $r^n$, and some power of v, say $v^m$. Which of the following is the simplest form of an equation for the acceleration?
asked
Jun 17, 2013
by
meena.p
jeemain
physics
class11
ch2
units-and-measurement
medium
dimensional-formulae-and-analysis
0
votes
1
answer
Given that the pressure $p$ at a depth $h$ below the surface of a fluid of density $\rho$ is given by $p = \rho gh$, where $g$ is the acceleration due to gravity, which of the following represent the dimensions of pressure?
asked
Jul 11, 2014
by
balaji.thirumalai
jeemain
physics
class11
units-and-measurement
ch2
dimensional-formulae-and-analysis
easy
Ask Question
SUBMIT QUESTION
►
Please Wait
Take Test
JEEMAIN Crash Practice
15 Test Series
NEET Crash Practice
5 Test Series
JEEMAIN
350+ TESTS
NEET
320+ TESTS
CBSE XI MATH
50+ TESTS
CBSE XII MATH
80+ TESTS
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...