Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Communication Systems
0 votes

A transmitting antenna at the top of a tower has a height 32 m and the height of the receiving antenna is 50 m. What is the maximum distance between them for satisfactory communication in LOS mode? Given radius of earth 6.4 $\times$ 106 m.

Can you answer this question?

1 Answer

0 votes
The maximum line-of-sight distance $d_M$ between two antennas having heights $h_T$ and $h_R$ above the earth is given by $d_M = \sqrt {2Rh_T} + \sqrt {2Rh_R}$ where $h_T$ and $h_R$ are the heights of the transmitting and receiving antennae.
Substituing, we get: $d_M = \sqrt { 2 \times 64 \times 10^5 \times 32} + \sqrt {2 \ times 64 \times 10^5 \times 50}\;m$
$d_M \;= 64 \times 10^2 \sqrt{10} + 8 \times 10^3 \times \sqrt{10}\;m$
$\quad \;\; =144 \times 10^2 \times \sqrt {10} \;m= 45.5\; km$
answered Jul 12, 2014 by balaji.thirumalai

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App