logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Communication Systems
0 votes

A transmission tower at a particular place has a height of 160m. (A) What is its coverage range? (B) By how much should the height be increased to double its coverage range? Given that radius of earth = 6400 km.

Can you answer this question?
 
 

1 Answer

0 votes
Let $h$ be height of tower, $d$ be radius of coverage, and $R$ the radius of earth $\rightarrow$ $d=\sqrt{2Rh}$
Given $R = 6400 \;km$, and $h = 160\;m$, $d = \sqrt {2 \times 6400 \times 10^3 \times 160} = 45.255 \;km$
To calculate the new height to double the coverage $\rightarrow \large\frac{d_1}{d_2}$$= \sqrt {\large\frac{h_1}{h2}}$
Given $d_2 = 2\times d_1$ and $h_1 = 160\;m$, we can calculate $h_2 = 160\times \large\frac{2^2}{1^1}$$ = 160 \times 4 = 640\;m$
answered Jul 12, 2014 by balaji.thirumalai
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...