Let $h$ be height of tower, $d$ be radius of coverage, and $R$ the radius of earth $\rightarrow$ $d=\sqrt{2Rh}$

Given $R = 6400 \;km$, and $h = 160\;m$, $d = \sqrt {2 \times 6400 \times 10^3 \times 160} = 45.255 \;km$

To calculate the new height to double the coverage $\rightarrow \large\frac{d_1}{d_2}$$= \sqrt {\large\frac{h_1}{h2}}$

Given $d_2 = 2\times d_1$ and $h_1 = 160\;m$, we can calculate $h_2 = 160\times \large\frac{2^2}{1^1}$$ = 160 \times 4 = 640\;m$