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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Communication Systems
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If the maximum peak-to-peak voltage of an AM wave is 16mV and the minimum peak-to peak voltage is 4mV, calculate the modulation factor.

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Maximum voltage: $V_{max} = \large\frac{16}{2} $$= 8\;mV$
Minimum voltage: $V_{min} = \large\frac{4}{2} $$= 2\;mV$
Modulation factor = $\large\frac{V_{max} - V_{min}}{V_{max}+V_{min}}$
$\Rightarrow$ Modulation factor $ = \large\frac{8-2}{8+2}$$ = 0.6$
answered Jul 12, 2014 by balaji.thirumalai

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