# When 80% AM is transmitted total power is 10kW. What is the power saved if the carrier and one side band are suppressed?

The total power in an AM signal when the carrier power and the percentage of modulation are known is $P_T = P_c \big ( 1 + \large\frac{m^2}{2}$$\big ) \Rightarrow P_c = \Large\frac{\normalsize 10}{1 + \Large\frac{0.8^2}{2}}$$ = 7.58\;kW$
$\Rightarrow$ Power Saved $= P_c \big (1 + \large\frac{m^2}{4} $$\big ) \quad \quad\quad \;\quad\quad = 7.58 \big (1+\large\frac{0.8^4}{4}$$\big)$$= 8.78\;kW$