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A transmitter puts out a total power of 32 Watts of 28% AM signal. Calculate how much power is contained in each of the sidebands and the fraction of power in the carrier.

1 Answer

The total power in an AM signal when the carrier power and the percentage of modulation are known is $P_T = P_c \big ( 1 + \large\frac{m^2}{2}$$\big )$
$\Rightarrow 32 = P_c \big ( 1 + \large\frac{0.28^2}{2}$$\big )$
$\Rightarrow P_c = \large\frac{32}{1.0392}$$ = 30.793\;W$
The total power in both side bands $ = 32-30.793 = 1.207\;W$
The power in each side band is half of this $ \approx 0.60\;W$
$\Rightarrow$ The fraction of the power in the carrier is $\large\frac{30.79}{32} $$\approx 0.96$
answered Jul 13, 2014 by balaji.thirumalai
edited Jul 13, 2014 by balaji.thirumalai

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