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A semiconductor has an electron concentration of $0.45 \times 10^{22} \; /m^3$ and a hole concentration of $5 \times 10^{20} \;/ m^3$. Find its conductivity.

Note: $\mu_c = 0.135 \; m^2/V-S, \;\mu_h = 0.048\; m^2/V-S.$
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The conductivity $\sigma = e\; (n_c \mu_c + n_h \mu_h)$
$\Rightarrow \sigma = 1.6 \times 10^{-19} (0.45 \times 10^{22} \times 0.135 + 5 \times 10^{20} \times 0.048)$
$\Rightarrow \sigma = 3.85\; \Omega^{-1}\;m^{-1}$
answered Jul 13, 2014 by balaji.thirumalai
 

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