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Given $n_i = 2.4 \times 10^{19} m^{-3}, \; \mu_n = 0.39\;m^2/V.S, \; \mu_p = 0.19\;m^2/V.s$ for intrinsic Ge at room temperature of $300^{\circ}\;K$, calculate the conductivity of the sample.

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In a pure semiconductor, $n = p = n_i$, the intrinsic conductivity is: $\sigma_i = (n\mu_n+p\mu_p) e = (\mu_n+\mu_p) \times e\;n_i$.
$\Rightarrow \sigma_p = 2.4 \times 10^{19} \times 1.6 \times 10^{-19} (0.39+0.19)$
$\quad \sigma_p = 2.22 \;\Omega^{-1}\;m^{-1}$
answered Jul 13, 2014 by balaji.thirumalai

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