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A genetically diseased male marries a normal female producing three diseased girls and five normal sons.It would be a

$\begin{array}{1 1}(A)\;\text{*** influenced disease}\\(B)\;\text{***-linked disease}\\(C)\;\text{*** recessive disease}\\(D)\;\text{Blood group inheritance disease}\end{array} $

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***-linked disease
Hence (B) is the correct answer.
answered Jul 14, 2014 by sreemathi.v
 

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