Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Motion in a Plane
0 votes

The range of projectile which is launch at an angle of $15^{\circ}$ with the horizontal is $1.5 \;km$ what is the range of the projectile if it is projected at an angle of $45^{\circ}$ to the horizontal ?

$\begin{array}{1 1}(A)\;1.5 km\\(B)\;3.0\;km \\(C)\;6.0 km\\(D)\;0.75 \;km \end{array} $

Can you answer this question?

1 Answer

0 votes
$\large\frac{R_2}{R_1} = \frac{\sin 2 \theta_2}{\sin 2 \theta_1} =\large\frac{\sin 90^{\circ}}{\sin 30^{\circ}}$
$\qquad= 2$ (near value is 1.5)
Hence A is the correct answer.
answered Jul 14, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App