$\begin{array}{1 1}(A)\;4.9 \;m\\(B)\;9.6\;m \\(C)\;19.6\;m\\(D)\;14 \;m \end{array} $

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+1 vote

+1 vote

Answer :$(B)\;9.6\;m$

$\overrightarrow{v} = 6 \hat {i} +8 \hat {j}$

Comparing with

$ \overrightarrow {v} = v_x \hat i = v_y \hat j$ we get,

$v_x = 6 ms^{-1}$

$v_y= 8 ms^{-1}$

Also, $v^2 =v_x^2 +v_y^2$

$\qquad= 36+64 =100$

or $v= 10 ms^{-1}$

$\sin \theta = \large\frac{8}{10}$ and $ \cos \theta= \large\frac{6}{10}$

$R= \large\frac{v^2 \sin 2 \theta}{g} =\frac{2v^2 \sin \theta \cos \theta}{g}$

$R= 2 \times 10 \times 10 \times \large\frac{8}{10} \times \frac{6}{19}\times \frac{1}{10} $$\;m$

$\qquad=9.6 \;m$

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