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# A body is projected at an angle $30^{\circ}$ to the horizontal with a speed $39.2 ms^{-1}$.What is the angle of projectile with the horizontal after 2 seconds ? (take $g= 9.8\;ms^{-2} )$

$\begin{array}{1 1}(A)\;0^{\circ}\\(B)\;30^{\circ} \\(C)\;60^{\circ}\\(D)\;90^{\circ} \end{array}$

$v_y= v_{0y}-gt=39.2 \sin 30^{\circ}-(9.8)(2)=0$
$v_x =v_0=39.2 \cos 30^{\circ}$
$\tan \theta= \large\frac{ u_y}{u_x} = \frac{0}{v_x}$$=0$
Hence A is the correct answer.