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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Motion in a Plane
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A body is projected at an angle $30^{\circ}$ to the horizontal with a speed $39.2 ms^{-1}$.What is the angle of projectile with the horizontal after 2 seconds ? (take $g= 9.8\;ms^{-2} )$

$\begin{array}{1 1}(A)\;0^{\circ}\\(B)\;30^{\circ} \\(C)\;60^{\circ}\\(D)\;90^{\circ} \end{array} $

Can you answer this question?

1 Answer

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$v_y= v_{0y}-gt=39.2 \sin 30^{\circ}-(9.8)(2)=0$
$ v_x =v_0=39.2 \cos 30^{\circ}$
$\tan \theta= \large\frac{ u_y}{u_x} = \frac{0}{v_x} $$ =0$
Hence A is the correct answer.
answered Jul 14, 2014 by meena.p

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