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# A body is projected with speed $v_1$ at an angle of $45^{\circ}$ to the horizontal from a point A. At the same instant, another body is projected vertically below the highest point of the path of the first body, Both the bodies will collide if $v_1/v_2$ is

$\begin{array}{1 1}(A)\;\sqrt {2} \\(B)\;\frac{1}{\sqrt 2} \\(C)\;\frac{1}{2}\\(D)\;2 \end{array}$

For collision $v_1 \sin 45^{\circ}=v_2$
Hence A is the correct answer.

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