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Marriage between colourblind woman and a normal man results in

$\begin{array}{1 1}(A)\;\text{Carrier daughters and colourblind sons}\\(B)\;\text{All colourblind}\\(C)\;\text{50% colourblind and 50% normal}\\(D)\;\text{25% colourblind and 25% normal}\end{array} $

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Marriage between colourblind woman and a normal man results in all colourblind
Hence (B) is the correct answer.
answered Jul 14, 2014 by sreemathi.v
 

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