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Questions  >>  CBSE XI  >>  Math  >>  Conic Sections
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Q)

Find the equation of the parabola that satisfies the given conditions : Focus (6,0); directrix x = – 6

$\begin {array} {1 1} (A)\;y^2=-24x & \quad (B)\;y^2=24x \\ (C)\;x^2=-24y & \quad (D)\;x^2=-24y \end {array}$

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A)
Toolbox:
  • If the coordinates of focis is (a, 0) then the parabola is open rightward.
  • The equaton of the parabola is $y^2=4ax$
Step 1 :
Given focus is (6, 0)
Equation of directrix is x = -6
Since the focus lies on the positive side of x - axis.
The axis of the parabola is x - axis.
Hence the equation of the parabola is
$y^2=4ax$
Substituting for $a$ we get,
$y^2=4 \times 6 \times x $
$ \Rightarrow y^2=24x$ is the equation of the parabola.
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