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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Motion in a Plane
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A man can throw a stone 60 m away . How high can he throw the stone vertically upward?

$\begin{array}{1 1}(A)\;2m \\(B)\;30 m \\(C)\;40 m\\(D)\;25 m \end{array} $

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1 Answer

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The maximum range given by $R_{max} =\large\frac{v_0^2}{g} $
This shows that the man can throw a stone with a maximum velocity $v_0 = \sqrt { g R_{max}}$.
When he throws the stone vertically upwards with this velocity , the maximum height $H_{max} $ reached is given by
$0= v_0^2 -2gh_{max}$
$H_{max}=\large\frac{v_0^2}{2g} =\frac{gR_{max}}{2g}$
Here $R_{max} =60 \;m$ hence $H_{max} =30 m$
Hence B is the correct answer.
answered Jul 15, 2014 by meena.p
 

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