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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Motion in a Plane

A ball rolls off the top of a stairway with a velocity u. If the height of each step is h, the breadth is b and the ball hits the edge of nth steps, the find the value of n.

$\begin{array}{1 1}(A)\;2hu \\(B)\;\frac{2hu^2}{gb^2} \\(C)\;\frac{1}{2}hu\\(D)\;0 \end{array} $

1 Answer

Horizontal distance covered by ball =nb
Vertical distance covered by ball =nh
If the time taken to hit the edge of nth step is t, then
$nb= ut$
$nh= \large\frac{1}{2}$$gt^2$
Eliminating t, we get,
$nh = \large\frac{1}{2}$$g \bigg(\large\frac{nb}{u}\bigg)^2$
$n= \large\frac{2hu^2}{gb^2}$
Hence B is the correct answer.
answered Jul 15, 2014 by meena.p
 

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