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Q)

What is the total number of atoms in a cubic based unit cell having one atom on each corner and two atoms on each diagonal?

$\begin{array}{1 1} 8 \\ 12 \\ 9 \\ 11 \end{array}$

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A)
Answer: $9$ atoms.
Number of atoms contributed by 8 corner atoms $ = \large\frac{1}{8}$$\times 8 = 1$
Number of atoms contributed by 4 diagonals $ = 4 \times 2 = 8 $
$\Rightarrow $ the total number of atoms $= 1 + 8 = 9$.
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