Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Motion in a Plane
0 votes

The equation of trajectory of a projectile is given by $y=x -\large\frac{x^2}{100}$ Find the range .

$\begin{array}{1 1}(A)\;100\;m \\(B)\;200\;m \\(C)\;300\;m\\(D)\;2m \end{array} $

Can you answer this question?

1 Answer

0 votes
Comparing $y=x -\large\frac{x^2}{100}$
with $y=\tan\theta  x-\large\frac{1}{2} \frac{g}{u^2 \cos ^2 \theta}$$x^2$
we get that the value of $\theta=45$
$R=\large\frac{v_0^2 \sin 2 \theta }{g}$
$\quad= \large\frac{1000 \sin 90^{\circ}}{10}$
$\quad=100 m$
Hence A is the correct answer.


answered Jul 16, 2014 by meena.p
edited Aug 14, 2014 by thagee.vedartham

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App